monicatserendavaa226
monicatserendavaa226 monicatserendavaa226
  • 02-06-2024
  • Mathematics
contestada

pls help i’m confused

pls help im confused class=

Respuesta :

olumideolawoyin
olumideolawoyin olumideolawoyin
  • 02-06-2024

Answer:

X = 50.5°

Step-by-step explanation:

Using Cosine rule, A X

[tex] {a}^{2} = {b}^{2} + {c}^{2} - 2bc \: CosA[/tex]

In the diagram, X = A, therefore;

[tex]CosA \: = \frac{ {b}^{2} + {c}^{2} - {a}^{2} }{2bc} [/tex]

[tex]Cos \: X \: = \frac{ {{10}^{2} + {11}^{2} - {9}^{2} } }{2 \times 11 \times 10} [/tex]

[tex] = \frac{100 + 121 - 81}{220} [/tex]

[tex] = \frac{140}{220} = \frac{14}{22} = \frac{7}{11} [/tex]

X = arc cos (7 /11)

X = 50.4788°

X = 50.5°

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